Physics · 2016
NEET 2016 · 1 May · Code Y · Q116
The intensity at the maximum in a Young's double slit experiment is I_0. Distance between two slits is d =5 λ, where λ is the wavelength of light…
The intensity at the maximum in a Young's double slit experiment is $\displaystyle \mathrm{I}_0$. Distance between two slits is $\displaystyle \mathrm{d}=5 \lambda$, where $\displaystyle \lambda$ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance $\displaystyle \mathrm{D}=10 \mathrm{~d}$ ?
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{\mathrm{I}_0}{2}$
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NEET (UG) 2016 Physics question, with the answer from NTA’s final answer key. Where our answers come from.