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Physics · 2011

NEET 2011 · Prelims · Code A · Q6

The instantaneous angular position of a point on a rotating wheel is given by the equation θ( t )=2 t^3-6 t^2 The torque on the wheel becomes zero at:

The instantaneous angular position of a point on a rotating wheel is given by the equation $\displaystyle \theta(\mathrm{t})=2 \mathrm{t}^3-6 \mathrm{t}^2$ The torque on the wheel becomes zero at :
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NEET (UG) 2011 Physics question, with the answer from NTA’s final answer key. Where our answers come from.