Physics · 2009
NEET 2009 · Prelims · Code A · Q30
The electric potential at a point (x, y, z) is given by: V =-x^2 y-x z^3+4 The electric field E at that point is:
The electric potential at a point $\displaystyle (x, y, z)$ is given by :
$$\mathrm{V}=-x^2 y-x z^3+4
$$
The electric field $\displaystyle \overrightarrow{\mathrm{E}}$ at that point is :
Official answer
(2)
$\displaystyle \overrightarrow{\mathrm{E}}=\hat{i}\left(2 x y+z^3\right)+\hat{j} x^2+\hat{k} 3 x z^2$
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NEET (UG) 2009 Physics question, with the answer from NTA’s final answer key. Where our answers come from.