Physics · 2010
NEET 2010 · Prelims · Code A · Q18
The displacement of a particle along the x axis is given by x= a sin^2 ω t. The motion of the particle corresponds to:
The displacement of a particle along the $\displaystyle x$ axis is given by $\displaystyle x=\mathrm{a} \sin ^2 \omega \mathrm{t}$. The motion of the particle corresponds to :
Official answer
(2)
simple harmonic motion of frequency $\displaystyle \omega / \pi$
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NEET (UG) 2010 Physics question, with the answer from NTA’s final answer key. Where our answers come from.