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Physics · 2020

NEET 2020 · 14 October · Code Z6 · Q99

The acceleration of an electron due to the mutual attraction between the electron and a proton when they are 1.6 apart is. (m_e ≃ 9 × 10^-31 kg,…

The acceleration of an electron due to the mutual attraction between the electron and a proton when they are $\displaystyle 1.6 \AA$ apart is. $$\left(m_e \simeq 9 \times 10^{-31} \mathrm{~kg}, \quad e=1.6 \times 10^{-19} \mathrm{C}\right) $$ (Take $\displaystyle \frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \mathrm{~N} \mathrm{~m}^2 \mathrm{C}^{-2}$ )
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NEET (UG) 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.