Physics · 2016
NEET 2016 · 1 May · Code Y · Q122
If the velocity of a particle is v= At + Bt^2, where A and B are constants, then the distance travelled by it between 1s and 2s is:
If the velocity of a particle is $\displaystyle v=\mathrm{At}+\mathrm{Bt}^2$, where $\displaystyle A$ and $\displaystyle B$ are constants, then the distance travelled by it between 1s and 2s is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \frac{3}{2} \mathrm{~A}+\frac{7}{3} \mathrm{~B}$
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NEET (UG) 2016 Physics question, with the answer from NTA’s final answer key. Where our answers come from.