Physics · 2021
NEET 2021 · 12 September · Code M1 · Q49
From a circular ring of mass 'M' and radius 'R' an arc corresponding to a 90° sector is removed. The moment of inertia of the remaining part of the…
From a circular ring of mass 'M' and radius 'R' an arc corresponding to a $\displaystyle 90$° sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is ' K ' times ' $\displaystyle \mathrm{MR}^2$ '. Then the value of ' K ' is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{3}{4}$
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NEET (UG) 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.