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Physics · 2026 · 4 marks
NEET 2026 · 21 June · Code 50 · Q6
Consider a particle moving along a straight line, whose position as a function of time is given by s(t)=α t^2-β t+γ, where α=1 ms^-2, β=6 ms^-1 and…
Consider a particle moving along a straight line, whose position as a function of time is given by $\displaystyle \mathrm{s}(\mathrm{t})=\alpha \mathrm{t}^2-\beta \mathrm{t}+\gamma$, where $\displaystyle \alpha=1 \mathrm{~ms}^{-2}$, $\displaystyle \beta=6 \mathrm{~ms}^{-1}$ and $\displaystyle \gamma=5 \mathrm{~m}$. The average speed of the particle, in $\displaystyle \mathrm{ms}^{-1}$, from $\displaystyle \mathrm{t}=0$ to $\displaystyle \mathrm{t}=6 \mathrm{~s}$ is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 3$
NEET (UG) 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.