A uniform rod of length 200 cm and mass 500 g is balanced on a wedge placed at 40 cm mark. A mass of 2 kg is suspended from the rod at 20 cm and…

A uniform rod of length $\displaystyle 200$ cm and mass $\displaystyle 500$ g is balanced on a wedge placed at $\displaystyle 40$ cm mark. A mass of $\displaystyle 2$ kg is suspended from the rod at $\displaystyle 20$ cm and another unknown mass 'm' is suspended from the rod at $\displaystyle 160$ cm mark as shown in the figure. Find the value of ' $\displaystyle m$ ' such that the rod is in equilibrium. $\displaystyle \left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$