Physics · 2010
NEET 2010 · Prelims · Code A · Q21
A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per sec when…
A tuning fork of frequency $\displaystyle 512$ Hz makes $\displaystyle 4$ beats per second with the vibrating string of a piano. The beat frequency decreases to $\displaystyle 2$ beats per sec when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was :
Official answer
(1)
$\displaystyle 508$ Hz
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NEET (UG) 2010 Physics question, with the answer from NTA’s final answer key. Where our answers come from.