Physics · 2014
NEET 2014 · 4 May · Code P · Q32
A thin semicircular conducting ring (PQR) of radius 'r' is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The…
A thin semicircular conducting ring (PQR) of radius 'r' is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The potential difference developed across the ring when its speed is v, is :
Official answer
From NTA’s final answer key for this paper.
(4)
2rBv and R is at higher potential
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NEET (UG) 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.