Physics · 2017
NEET 2017 · 7 May · Code A · Q23
A spring of force constant k is cut into lengths of ratio 1: 2: 3. They are connected in series and the new force constant is k^′ Then they are…
A spring of force constant k is cut into lengths of ratio $\displaystyle 1: 2: 3$. They are connected in series and the new force constant is $\displaystyle \mathrm{k}^{\prime}$ Then they are connected in parallel and force constant is $\displaystyle \mathrm{k}^{\prime \prime}$. Then $\displaystyle \mathrm{k}^{\prime}: \mathrm{k}^{\prime \prime}$ is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 1$ : $\displaystyle 11$
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NEET (UG) 2017 Physics question, with the answer from NTA’s final answer key. Where our answers come from.