Physics · 2009
NEET 2009 · Prelims · Code A · Q20
A simple pendulum performs simple harmonic motion about x=0 with an amplitude a and time period T. The speed of the pendulum at x=a / 2 will be:
A simple pendulum performs simple harmonic motion about $\displaystyle x=0$ with an amplitude $\displaystyle a$ and time period $\displaystyle T$. The speed of the pendulum at $\displaystyle x=a / 2$ will be :
Official answer
(1)
$\displaystyle \frac{\pi a \sqrt{3}}{T}$
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NEET (UG) 2009 Physics question, with the answer from NTA’s final answer key. Where our answers come from.