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Physics · 2026 · 4 marks
NEET 2026 · 21 June · Code 50 · Q19
A photon and an electron, each of 20 eV energy, move in free space. The ratio of linear momentum of electron p e to that of photon p Ph, p ep Ph is:…
A photon and an electron, each of $\displaystyle 20$ eV energy, move in free space. The ratio of linear momentum of electron $\displaystyle \mathrm{p}_{\mathrm{e}}$ to that of photon $\displaystyle \mathrm{p}_{\mathrm{Ph}}, \frac{\mathrm{p}_{\mathrm{e}}}{\mathrm{p}_{\mathrm{Ph}}}$ is :
(Take speed of light $\displaystyle =3 \times 10^8 \mathrm{~ms}^{-1}$, charge of electron $\displaystyle =-1.6 \times 10^{-19} \mathrm{C}$ and mass of electron $\displaystyle =9 \times 10^{-31} \mathrm{~kg}$ )
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 225$
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