Physics · 2020
NEET 2020 · 14 October · Code Z6 · Q128
A parallel plate capacitor having cross-sectional area A and separation d has air in between the plates. Now an insulating slab of same area but…
A parallel plate capacitor having cross-sectional area $\displaystyle A$ and separation $\displaystyle d$ has air in between the plates. Now an insulating slab of same area but thickness $\displaystyle d / 2$ is inserted between the plates as shown in figure having dielectric constant $\displaystyle K(=4)$. The ratio of new capacitance to its original capacitance will be,
Official answer
(1)
$\displaystyle 8$:$\displaystyle 5$
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