Physics · 2019
NEET 2019 · 20 May · Code G1 · Q138
A mass falls from a height ' h ' and its time of fall ' t ' is recorded in terms of time period T of a simple pendulum. On the surface of earth it is…
A mass falls from a height ' $\displaystyle h$ ' and its time of fall ' $\displaystyle t$ ' is recorded in terms of time period $\displaystyle T$ of a simple pendulum. On the surface of earth it is found that $\displaystyle \mathrm{t}=2 \mathrm{~T}$. The entire set up is taken on the surface of another planet whose mass is half of that of earth and radius the same. Same experiment is repeated and corresponding times noted as $\displaystyle \mathrm{t}^{\prime}$ and $\displaystyle \mathrm{T}^{\prime}$. Then we can say
Official answer
(4)
$\displaystyle \mathrm{t}^{\prime}=2 \mathrm{~T}^{\prime}$
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NEET (UG) 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.