Physics · 2013
NEET 2013 · 18 May · Code Y · Q97
A long straight wire carries a certain current and produces a magnetic field 2 × 10^-4 Weber/(m^2) at a perpendicular distance of 5 cm from the wire.…
A long straight wire carries a certain current and produces a magnetic field $\displaystyle 2 \times 10^{-4} \frac{\text { Weber }}{\mathrm{m}^2}$ at a perpendicular distance of $\displaystyle 5$ cm from the wire. An electron situated at $\displaystyle 5$ cm from the wire moves with a velocity $\displaystyle 10^7 \mathrm{~m} / \mathrm{s}$ towards the wire along perpendicular to it. The force experienced by the electron will be (charge on electron $\displaystyle 1.6 \times 10^{-19} \mathrm{C}$) :
Official answer
(4)
$\displaystyle 3.2 \times 10^{-16} \mathrm{~N}$
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NEET (UG) 2013 Physics question, with the answer from NTA’s final answer key. Where our answers come from.