SolveIt is under development
SolveItNEET (UG)
Physics · 2011

NEET 2011 · Mains · Code B · Q107

A conveyor belt is moving at a constant speed of 2m/s. A box is gently dropped on it. The coefficient of friction between them is μ=0.5. The distance…

A conveyor belt is moving at a constant speed of 2m/s. A box is gently dropped on it. The coefficient of friction between them is $\displaystyle \mu=0.5$. The distance that the box will move relative to belt before coming to rest on it taking $\displaystyle \mathrm{g}=10 \mathrm{~ms}^{-2}$, is :
ShareWhatsAppTelegram

More from Laws of Motion

NEET (UG) 2011 Physics question, with the answer from NTA’s final answer key. Where our answers come from.