Chemistry · 2019
NEET 2019 · 20 May · Code G1 · Q111
When neutral or faintly alkaline KMnO_4 is treated with potassium iodide, iodide ion is converted into ' X ', ' X ' is -
When neutral or faintly alkaline $\displaystyle \mathrm{KMnO}_4$ is treated with potassium iodide, iodide ion is converted into ' $\displaystyle X$ ', ' $\displaystyle X$ ' is -
Official answer
(3)
$\displaystyle \mathrm{IO}_3^{-}$
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NEET (UG) 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.