Chemistry · 2014
NEET 2014 · 4 May · Code P · Q53
When 22.4 litres of H_2( g ) is mixed with 11.2 litres of Cl_2( g ), each at S.T.P., the moles of HCl ( g ) formed is equal to:
When $\displaystyle 22.4$ litres of $\displaystyle \mathrm{H}_2(\mathrm{g})$ is mixed with $\displaystyle 11.2$ litres of $\displaystyle \mathrm{Cl}_2(\mathrm{g})$, each at S.T.P., the moles of $\displaystyle \mathrm{HCl}(\mathrm{g})$ formed is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 1$ mol of $\displaystyle \mathrm{HCl}(\mathrm{g})$
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NEET (UG) 2014 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.