What mass of 95 % pure CaCO_3 will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction? CaCO_3( s ) +2 HCl_( aq…

What mass of $\displaystyle 95 \%$ pure $\displaystyle \mathrm{CaCO}_3$ will be required to neutralise $\displaystyle 50$ mL of $\displaystyle 0.5$ M HCl solution according to the following reaction ? $\displaystyle \mathrm{CaCO}_{3(\mathrm{~s})}+2 \mathrm{HCl}_{(\mathrm{aq})} \rightarrow \mathrm{CaCl}_{2(\mathrm{aq})}+\mathrm{CO}_{2(\mathrm{~g})}+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})}$ [Calculate upto second place of decimal point]