Chemistry · 2011
NEET 2011 · Prelims · Code A · Q56
Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u.…
Two gases A and B having the same volume diffuse through a porous partition in $\displaystyle 20$ and $\displaystyle 10$ seconds respectively. The molecular mass of A is $\displaystyle 49$ u. Molecular mass of B will be :
Official answer
(3)
12.$\displaystyle 25$ u
More from States of Matter
- A gas such as carbon monoxide would be most likely to obey the ideal gas law at:2015
- Which amongst the following options is correct graphical representation of Boyle's Law?2023
- For real gases van der Waals equation is written as (p+(a n^2)/V^2)(V-n b)=n R T where ' a ' and ' b ' are van der Waals constants. Two sets of gases…2012
- Maximum deviation from ideal gas is expected from:2013
- A bubble of air is underwater at temperature 15°C and the pressure 1.5 bar. If the bubble rises to the surface where the temperature is 25°C and the…2011
- If a gas expands at constant temperature, it indicates that:2008
- A mixture of N_2 and Ar gases in a cylinder contains 7 g of N_2 and 8 g of Ar. If the total pressure of the mixture of the gases in the cylinder is…2020
- A certain gas takes three times as long to effuse out as helium. Its molecular mass will be:2012
NEET (UG) 2011 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.