The quantum numbers of four electrons are given below: I. n =4; l =2; m_l =-2; s =-1/2 II. n =3; l =2; m_l =1; s =+1/2 III. n =4; l =1; m_l =0; s…

The quantum numbers of four electrons are given below : I. $\displaystyle \mathrm{n}=4 ; \mathrm{l}=2 ; \mathrm{m}_{\mathrm{l}}=-2 ; \mathrm{s}=-\frac{1}{2}$ II. $\displaystyle \mathrm{n}=3 ; \mathrm{l}=2 ; \mathrm{m}_{\mathrm{l}}=1 ; \mathrm{s}=+\frac{1}{2}$ III. $\displaystyle \mathrm{n}=4 ; \mathrm{l}=1 ; \mathrm{m}_{\mathrm{l}}=0 ; \mathrm{s}=+\frac{1}{2}$ IV. $\displaystyle \mathrm{n}=3 ; \mathrm{l}=1 ; \mathrm{m}_{\mathrm{l}}=-1 ; \mathrm{s}=+\frac{1}{2}$ The correct decreasing order of energy of these electrons is