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Chemistry · 2026 · 4 marks
NEET 2026 · 21 June · Code 50 · Q67
The lanthanide ion having four unpaired electrons is (Given: Atomic numbers of Ce=58, Nd=60, Tb=65 and Ho=67 )
The lanthanide ion having four unpaired electrons is
(Given : Atomic numbers of $\displaystyle \mathrm{Ce}=58$, $\displaystyle \mathrm{Nd}=60, \mathrm{~Tb}=65$ and $\displaystyle \mathrm{Ho}=67$ )
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \mathrm{Ho}^{3+}$
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NEET (UG) 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.