Chemistry · 2021
NEET 2021 · 12 September · Code M1 · Q64
The following solutions were prepared by dissolving 10 g of glucose ( C_6 H_12 O_6) in 250 ml of water ( P_1), 10 g of urea ( CH_4 N_2 O ) in 250 ml…
The following solutions were prepared by dissolving $\displaystyle 10$ g of glucose $\displaystyle \left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)$ in $\displaystyle 250$ ml of water $\displaystyle \left(\mathrm{P}_1\right)$, $\displaystyle 10$ g of urea $\displaystyle \left(\mathrm{CH}_4 \mathrm{~N}_2 \mathrm{O}\right)$ in $\displaystyle 250$ ml of water $\displaystyle \left(\mathrm{P}_2\right)$ and $\displaystyle 10$ g of sucrose $\displaystyle \left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)$ in $\displaystyle 250$ ml of water $\displaystyle \left(\mathrm{P}_3\right)$. The right option for the decreasing order of osmotic pressure of these solutions is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \mathrm{P}_2>\mathrm{P}_1>\mathrm{P}_3$
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NEET (UG) 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.