The correct decreasing order of oxidation state of the underlined atom in each molecule is

$\displaystyle \underline{\mathrm{P}}_4 \mathrm{O}_{10}>\underline{\mathrm{S}} \mathrm{O}_3>\mathrm{H}_2 \underline{\mathrm{O}}$

$\displaystyle \underline{\mathrm{N}}_2 \mathrm{O}_5>\underline{\mathrm{Al}}_2 \mathrm{O}_3>\mathrm{H}_2 \underline{\mathrm{~S}}$

$\displaystyle \underline{\mathrm{Pb}} \mathrm{O}_2>\underline{\mathrm{N}}_2 \mathrm{O}_3>\underline{\mathrm{S}} \mathrm{O}_3$

$\displaystyle \underline{\mathrm{P}}_4 \mathrm{O}_6>\underline{\mathrm{Cl}}_2 \mathrm{O}_7>\underline{\mathrm{Al}} \mathrm{H}_3$