Chemistry · 2018
NEET 2018 · 6 May · Code AA · Q61
The compound C_7 H_8 undergoes the following reactions: C_7 H_8 → 3 Cl_2 / Δ A → Br_2 / Fe B → Zn / HCl C The product ' C ' is
The compound $\displaystyle \mathrm{C}_7 \mathrm{H}_8$ undergoes the following reactions :
$$\mathrm{C}_7 \mathrm{H}_8 \xrightarrow{3 \mathrm{Cl}_2 / \Delta} \mathrm{A} \xrightarrow{\mathrm{Br}_2 / \mathrm{Fe}} \mathrm{~B} \xrightarrow{\mathrm{Zn} / \mathrm{HCl}} \mathrm{C}
$$
The product ' C ' is
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle m$-bromotoluene
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NEET (UG) 2018 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.