Chemistry · 2024
NEET 2024 · 23 June · Code C1 · Q70
The amount of glucose required to prepare 250 mL of M/20 aqueous solution is: (Molar mass of glucose: 180 g mol^-1 )
The amount of glucose required to prepare $\displaystyle 250$ mL of $\displaystyle \frac{\mathrm{M}}{20}$ aqueous solution is :
(Molar mass of glucose : $\displaystyle 180 \mathrm{~g} \mathrm{~mol}^{-1}$)
Official answer
(1)
2.$\displaystyle 25$ g
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NEET (UG) 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.