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Chemistry · 2022

NEET 2022 · 4 September · Code W6 · Q51

Match List - I with List - II: Choose the correct answer from the options given below:

Match List - I with List - II :
List - IList - II
(quantum number)(orbital)
(a)$\displaystyle \mathrm{n}=2, \mathrm{l}=1$(i)3s
(b)$\displaystyle \mathrm{n}=3, \mathrm{l}=2$(ii)3s
(c)$\displaystyle \mathrm{n}=3, \mathrm{l}=0$(iii)2p
(d)$\displaystyle \mathrm{n}=2, \mathrm{l}=0$(iv)3d
Choose the correct answer from the options given below :
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NEET (UG) 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.