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Chemistry · 2022

NEET 2022 · 4 September · Code W6 · Q55

Match List - I with List - II: Choose the correct answer from the options given below:

Match List - I with List - II :
List - IList - II
(Compounds)(Molecular formula)
(a)Borax(i)$\displaystyle \mathrm{NaBO}_2$
(b)Kernite(ii)$\displaystyle \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 4 \mathrm{H}_2 \mathrm{O}$
(c)Orthoboric acid(iii)$\displaystyle \mathrm{H}_3 \mathrm{BO}_3$
(d)Borax bead(iv)$\displaystyle \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O}$
Choose the correct answer from the options given below :
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NEET (UG) 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.