Chemistry · 2022
NEET 2022 · 4 September · Code W6 · Q63
Na_2 B_4 O_7 → heat X + NaBO_2 in the above reaction the product "X" is:
$\displaystyle \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \xrightarrow{\text { heat }} \mathrm{X}+\mathrm{NaBO}_2$
in the above reaction the product "X" is:
Official answer
(3)
$\displaystyle \mathrm{B}_2 \mathrm{O}_3$
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NEET (UG) 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.