Chemistry · 2014
NEET 2014 · 4 May · Code P · Q89
Identity Z in the sequence of reactions: CH_3 CH_2 CH = CH_2 → HBr / H_2 O_2 Y → C_2 H_5 ONa Z
Identity Z in the sequence of reactions :
$$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}=\mathrm{CH}_2 \xrightarrow{\mathrm{HBr} / \mathrm{H}_2 \mathrm{O}_2} \mathrm{Y} \xrightarrow{\mathrm{C}_2 \mathrm{H}_5 \mathrm{ONa}} \mathrm{Z}
$$
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \mathrm{CH}_3-\left(\mathrm{CH}_2\right)_3-\mathrm{O}-\mathrm{CH}_2 \mathrm{CH}_3$
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NEET (UG) 2014 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.