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Chemistry · 2026 · 4 marks
NEET 2026 · 3 May · Code 11 · Q86
Given below is an expression for the rate constant of a first order reaction occurring at a certain temperature, T (K). ln k=14.34-(1.25 × 10^4)/( T)…
Given below is an expression for the rate constant of a first order reaction occurring at a certain temperature, T (K).
$\displaystyle \ln \mathrm{k}=14.34-\frac{1.25 \times 10^4}{\mathrm{~T}}$
The energy of activation in $\displaystyle \mathrm{kcal} \mathrm{mol}^{-1}$ for the reaction is :
(Given : k in $\displaystyle \mathrm{s}^{-1}, \mathrm{R}=1.987 \mathrm{cal} \mathrm{mol}^{-1} \mathrm{~K}^{-1}$ )
Official answer
From NTA’s provisional answer key for this paper. NTA published no final key for it.
(1)
$\displaystyle 24.84$
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NEET (UG) 2026 Chemistry question, with the answer from NTA’s provisional answer key. Where our answers come from.