SolveItNEET (UG)
✓ Board-verified
Chemistry · 2026 · 4 marks

NEET 2026 · 3 May · Code 11 · Q86

Given below is an expression for the rate constant of a first order reaction occurring at a certain temperature, T (K). ln k=14.34-(1.25 × 10^4)/( T)…

Given below is an expression for the rate constant of a first order reaction occurring at a certain temperature, T (K). $\displaystyle \ln \mathrm{k}=14.34-\frac{1.25 \times 10^4}{\mathrm{~T}}$ The energy of activation in $\displaystyle \mathrm{kcal} \mathrm{mol}^{-1}$ for the reaction is : (Given : k in $\displaystyle \mathrm{s}^{-1}, \mathrm{R}=1.987 \mathrm{cal} \mathrm{mol}^{-1} \mathrm{~K}^{-1}$ )

More from Chemical Kinetics

NEET (UG) 2026 Chemistry question, with the answer from NTA’s provisional answer key. Where our answers come from.