For the reaction: X_2 O_4( l ) → 2 XO_2( g ) Δ U =2.1 k cal, Δ S =20 cal K^-1 at 300 K Hence, Δ G is:

For the reaction : $\displaystyle \mathrm{X}_2 \mathrm{O}_4(\mathrm{l}) \rightarrow 2 \mathrm{XO}_2(\mathrm{g})$ $\displaystyle \Delta \mathrm{U}=2.1 \mathrm{k}$ cal, $\displaystyle \Delta \mathrm{S}=20 \mathrm{cal} \mathrm{K}^{-1}$ at $\displaystyle 300$ K Hence, $\displaystyle \Delta \mathrm{G}$ is :