Chemistry · 2008
NEET 2008 · Prelims · Code A · Q60
Bond dissociation enthalpy of H_2, Cl_2 and HCl are 434, 242 and 431 kJmol^-1 respectively. Enthalpy of formation of HCl is:
Bond dissociation enthalpy of $\displaystyle \mathrm{H}_2, \mathrm{Cl}_2$ and HCl are $\displaystyle 434$, $\displaystyle 242$ and $\displaystyle 431 \mathrm{kJmol}^{-1}$ respectively. Enthalpy of formation of HCl is :
Official answer
(4)
$\displaystyle -93 \mathrm{kJmol}^{-1}$
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