Chemistry · 2012
NEET 2012 · Mains · Code C · Q109
Activation energy ( E_a ) and rate constants ( k_1 and k_2 ) of a chemical reaction at two different temperatures ( T_1 and T_2 ) are related by:
Activation energy ( $\displaystyle \mathrm{E}_{\mathrm{a}}$ ) and rate constants ( $\displaystyle \mathrm{k}_1$ and $\displaystyle \mathrm{k}_2$ ) of a chemical reaction at two different temperatures ( $\displaystyle \mathrm{T}_1$ and $\displaystyle \mathrm{T}_2$ ) are related by :
Official answer
(2)
$\displaystyle \ln \frac{\mathrm{k}_2}{\mathrm{k}_1}=\frac{\mathrm{E}_{\mathrm{a}}}{\mathrm{R}}\left(\frac{1}{\mathrm{~T}_1}-\frac{1}{\mathrm{~T}_2}\right)$
(4)
$\displaystyle \ln \frac{\mathrm{k}_2}{\mathrm{k}_1}=-\frac{\mathrm{E}_{\mathrm{a}}}{\mathrm{R}}\left(\frac{1}{\mathrm{~T}_2}-\frac{1}{\mathrm{~T}_1}\right)$
NTA’s answer key accepts either.
More from Chemical Kinetics
- For a certain reaction R → Product, the plot of concentration [R] vs time has a negative slope as shown. The order of reaction is:2026
- The correct difference between first- and second-order reactions is that2018
- The rate of a reaction quadruples when temperature changes from 27^° C to 57^° C. Calculate the energy of activation. Given R=8.314 J K^-1 mol^-1,…2024
- The rate of a first-order reaction is 0.04 mol l^-1 s^-1 at 10 seconds and 0.03 mol l^-1 s^-1 at 20 seconds after initiation of the reaction. The…2016
- During the kinetic study of the reaction, 2 A+B → C+D, following results were obtained: Based on the above data which one of the following is correct?2010
- The addition of a catalyst during a chemical reaction alters which of the following quantities?2016
- Mechanism of a hypothetical reaction X_2+Y_2 → 2 XY is given below (i) X_2 → X+X (fast) (ii) X+Y_2 ⇌ XY+Y (slow) (iii) X+Y → XY (fast) The overall…2017
- For an endothermic reaction, energy of activation is E_a and enthalpy of reaction is Δ H (both of these in kJ/mol). Minimum value of E_a will be:2010
NEET (UG) 2012 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.