Chemistry · 2013
NEET 2013 · 18 May · Code Y · Q163
According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as ( h =6.62 × 10^-27 ergs, c =3 × 10^10 cm s^-1, N_A =6.02…
According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as ( $\displaystyle \mathrm{h}=6.62 \times 10^{-27}$ ergs, $\displaystyle \mathrm{c}=3 \times 10^{10} \mathrm{~cm} \mathrm{~s}^{-1}$, $\displaystyle \mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23} \mathrm{~mol}^{-1}$ )
Official answer
(3)
$\displaystyle \frac{1.196 \times 10^8}{\lambda}$
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NEET (UG) 2013 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.