Physics · 2022
JEE Main · 29 June 2022, Shift 1 · Q43
Two vectors A and B have equal magnitudes. If magnitude of A + B is equal to two times the magnitude of A - B, then the angle between A and B will be:
Two vectors $\displaystyle \vec{A}$ and $\displaystyle \vec{B}$ have equal magnitudes. If magnitude of $\displaystyle \vec{A}+\vec{B}$ is equal to two times the magnitude of $\displaystyle \vec{A}-\vec{B}$, then the angle between $\displaystyle \vec{A}$ and $\displaystyle \vec{B}$ will be :
Official answer
(3)
$\displaystyle \cos ^{-1}\left(\frac{3}{5}\right)$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.