Physics · 2013
JEE Main · 22 April 2013, Shift 1 · Q23
Two small equal point charges of magnitude q are suspended from a common point on the ceiling by insulating massless strings of equal lengths. They…
Two small equal point charges of magnitude q are suspended from a common point on the ceiling by insulating massless strings of equal lengths. They come to equilibrium with each string making angle $\displaystyle \theta$ from the vertical. If the mass of each charge is $\displaystyle m$, then the electrostatic potential at the centre of line joining them will be $\displaystyle \left(\frac{1}{4 \pi \epsilon_0}=\mathrm{k}\right)$.
Official answer
(4)
$\displaystyle 4 \sqrt{\mathrm{kmg} \tan \theta}$
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JEE Main 2013 Physics question, with the answer from NTA’s final answer key. Where our answers come from.