Physics · 2019
JEE Main · 9 January 2019, Shift 2 · Q16
Two point charges q_1(√ 10 μ C ) and q_2(-25 μ C ) are placed on the x -axis at x=1 m and x=4 m respectively. The electric field (in V / m ) at a…
Two point charges $\displaystyle \mathrm{q}_1(\sqrt{10} \mu \mathrm{C})$ and $\displaystyle \mathrm{q}_2(-25 \mu \mathrm{C})$ are placed on the $\displaystyle x$-axis at $\displaystyle x=1 \mathrm{~m}$ and $\displaystyle x=4 \mathrm{~m}$ respectively. The electric field (in $\displaystyle \mathrm{V} / \mathrm{m}$ ) at a point $\displaystyle y=3 \mathrm{~m}$ on $\displaystyle y$-axis is,
$$\left[\text { take } \frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}\right]
$$
Official answer
(2)
$\displaystyle (63 \hat{\mathrm{i}}-27 \hat{\mathrm{j}}) \times 10^2$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.