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Physics · 2021

JEE Main · 3 August 2021, Shift 2 · Q26

Two particles of equal mass ' m ' go round a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle…

Two particles of equal mass ' $\displaystyle m$ ' go round a circle of radius $\displaystyle R$ under the action of their mutual gravitational attraction. The speed of each particle is $\displaystyle \sqrt{\frac{1}{x} \cdot \frac{G m}{R}}$ where $\displaystyle x$ is \_\_\_\_.
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.