Two metallic wires P and Q have same volume and are made up of same material. If their area of cross sections are in the ratio 4: 1 and force F_1 is…

Two metallic wires $\displaystyle P$ and $\displaystyle Q$ have same volume and are made up of same material. If their area of cross sections are in the ratio $\displaystyle 4: 1$ and force $\displaystyle \mathrm{F}_1$ is applied to $\displaystyle P$, an extension of $\displaystyle \Delta l$ is produced. The force which is required to produce same extension in $\displaystyle Q$ is $\displaystyle \mathrm{F}_2$.The value of $\displaystyle \frac{F_1}{F_2}$ is $\displaystyle \_\_\_\_$.