Physics · 2019
JEE Main · 9 April 2019, Shift 2 · Q10
Two materials having coefficients of thermal conductivity ' 3 K ' and ' K ' and thickness 'd' and '3d', respectively, are joined to form a slab as…
Two materials having coefficients of thermal conductivity ' $\displaystyle 3$ K ' and ' K ' and thickness 'd' and '3d', respectively, are joined to form a slab as shown in the figure. The temperatures of the outer surfaces are ' $\displaystyle \theta_2$ ' and ' $\displaystyle \theta_1$ ' respectively, $\displaystyle \left(\theta_2>\theta_1\right)$. The temperature at the interface is :
Official answer
(4)
$\displaystyle \frac{\theta_1}{10}+\frac{9 \theta_2}{10}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.