Physics · 2020
JEE Main · 3 September 2020, Shift 2 · Q16
Two light waves having the same wavelength λ in vacuum are in phase initially. Then the first wave travels a path L_1 through a medium of refractive…
Two light waves having the same wavelength $\displaystyle \lambda$ in vacuum are in phase initially. Then the first wave travels a path $\displaystyle \mathrm{L}_1$ through a medium of refractive index $\displaystyle \mathrm{n}_1$ while the second wave travels a path of length $\displaystyle \mathrm{L}_2$ through a medium of refractive index $\displaystyle \mathrm{n}_2$. After this the phase difference between the two waves is:
Official answer
(2)
$\displaystyle \frac{2 \pi}{\lambda}\left(\mathbf{n}_1 \mathbf{L}_1-\mathbf{n}_2 \mathbf{L}_2\right)$
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