Physics · 2019
JEE Main · 12 January 2019, Shift 1 · Q12
Two light identical springs of spring constant k are attached horizontally at the two ends of a uniform horizontal rod AB of length l and mass m. The…
Two light identical springs of spring constant k are attached horizontally at the two ends of a uniform horizontal rod AB of length $\displaystyle l$ and mass m. The rod is pivoted at its centre ' O ' and can rotate freely in horizontal plane. The other ends of the two springs are fixed to rigid supports as shown in figure. The rod is gently pushed through a small angle and released. The frequency of resulting oscillation is :
Official answer
(4)
$\displaystyle \frac{1}{2 \pi} \sqrt{\frac{6 \mathrm{k}}{\mathrm{~m}}}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.