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Physics · 2021

JEE Main · 4 August 2021, Shift 2 · Q22

Two heaters X and Y are connected is parallel across the supply of V volts. Heater X generates 500 kCal of heat in 20 minutes while Y generates 1000…

Two heaters X and Y are connected is parallel across the supply of V volts. Heater X generates $\displaystyle 500$ kCal of heat in $\displaystyle 20$ minutes while Y generates $\displaystyle 1000$ kCal in $\displaystyle 10$ minutes. The resistance of heater X is $\displaystyle 10 \Omega$. If these heaters are connected in series across the same voltage, then the heat produced in $\displaystyle 5$ minutes will be \_\_\_\_ kCal.
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.