Physics · 2013
JEE Main · 22 April 2013, Shift 1 · Q13
To find the resistance of a galvanometer by the half deflection method the following circuit is used with resistances R_1=9970 Ω, R_2=30 Ω and R_3=0.…
To find the resistance of a galvanometer by the half deflection method the following circuit is used with resistances $\displaystyle \mathrm{R}_1=9970 \Omega, \mathrm{R}_2=30 \Omega$ and $\displaystyle \mathrm{R}_3=0$. The deflection in the galvanometer is d . With $\displaystyle \mathrm{R}_3=107 \Omega$ the deflection changed to $\displaystyle \frac{\mathrm{d}}{2}$. The galvanometer resistance is approximately :
Official answer
(4)
$\displaystyle 77 \Omega$
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JEE Main 2013 Physics question, with the answer from NTA’s final answer key. Where our answers come from.