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JEE Main · 10 January 2019, Shift 2 · Q29

The Wheatstone bridge shown in Fig. here, gets balanced when the carbon resistor used as R_1 has the colour code (Orange, Red, Brown). The resistors…

The Wheatstone bridge shown in Fig. here, gets balanced when the carbon resistor used as $\displaystyle \mathrm{R}_1$ has the colour code (Orange, Red, Brown). The resistors $\displaystyle \mathrm{R}_2$ and $\displaystyle \mathrm{R}_4$ are $\displaystyle 80 \Omega$ and $\displaystyle 40 \Omega$, respectively. Assuming that the colour code for the carbon resistors gives their accurate values, the colour code for the carbon resistor, used as $\displaystyle \mathrm{R}_3$, would be : Figure: JEE Main Physics 2019, Current Electricity
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