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Physics · 2021

JEE Main · 4 August 2021, Shift 2 · Q28

The voltage between the plates of a capacitor of capacitance 5 μ F is changing at a rate of 8 × 10^2 V/s. The displacement current is \ \ \ \ mA.

The voltage between the plates of a capacitor of capacitance $\displaystyle 5 \mu \mathrm{~F}$ is changing at a rate of $\displaystyle 8 \times 10^2 \frac{\mathrm{~V}}{\mathrm{~s}}$. The displacement current is \_\_\_\_ mA .
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.