Physics · 2021
JEE Main · 16 March 2021, Shift 1 · Q24
The value of power dissipated across the zener diode ( V_z =15 V ) connected in the circuit as shown in the figure is x × 10^-1 watt. The value of x,…
The value of power dissipated across the zener diode $\displaystyle \left(\mathrm{V}_{\mathrm{z}}=15 \mathrm{~V}\right)$ connected in the circuit as shown in the figure is $\displaystyle x \times 10^{-1}$ watt.
The value of $\displaystyle x$, to the nearest integer, is \_\_\_\_.
The value of $\displaystyle x$, to the nearest integer, is \_\_\_\_.Official answer
5
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.